P(x)=x^2-7x^2+36

Solution for P(x)=x^2-7x^2+36 equation:

(P)=P^2-7P^2+36

We move all terms to the left:

(P)-(P^2-7P^2+36)=0

We get rid of parentheses

-P^2+7P^2+P-36=0

We add all the numbers together, and all the variables

6P^2+P-36=0

a = 6; b = 1; c = -36;
Δ = b2-4ac
Δ = 12-4·6·(-36)
Δ = 865
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$P_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{865}}{2*6}=\frac{-1-\sqrt{865}}{12}
$
$P_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{865}}{2*6}=\frac{-1+\sqrt{865}}{12}
$